Question

In the below figure if AP=BP, AQ=BQ, then AM=BM?

• A. True
• B. False
• C. Data insufficient
• D. Cannot be determined

Answer 1

The correct option is A True

In the given figure,
AP = BP (Given)
AQ = BQ (Given)
PQ is common.
So, $\Delta$ PAQ $\cong$ $\Delta$ PBQ (SSS rule).
$\Rightarrow \angle$ APQ=$\angle$ BPQ (CPCT).
Also, AP = BP (Given) and PM is common
Hence, $△$ PMA $\cong$ $△$PMB (SAS Rule)

So, AM = BM