Every Point on the Bisector of an Angle Is Equidistant from the Sides of the Angle.
Question 6 In...
Question
Question 6 In the below figure, if ΔABE≅ΔACD, show that ΔADE∼ΔABC.
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Solution
It is given that ΔABE≅ΔACD. ∴AB=AC[ByCPCT]...(i) And, AD = AE [By CPCT] ... (ii) In ΔADE and ΔABC, ADAB=AEAC [Dividing equation (ii) by (i)] ∠A=∠ A [Common angle] ∴ΔADE∼ΔABC [By SAS similarity criterion]