Question

In the below figure the pressure gauge will record a gauge pressure equivalent to

• A. 6.12 m of water
• B. 1.21 m of mercury
• C. 0.5 bar
• D. 34,000 Pa

Answer 1

The correct option is C 0.5 bar

Let gauge pressure be = P
$P+(1.6\times {\rho }_w)\times g\times 0.7+(13.6\times {\rho }_w)\times g\times 0.25-(13.6\times {\rho }_w)\times g\times 0.7=0P=5\times g\times {\rho }_w=50000\frac{N}{m^2}=\frac{50000}{{10}^5}bar=0.5bar$