In the below quadrilateral ABCD, if AD = BC and ∠DAB = ∠CBA, then what is the relation between ∠ABD and ∠BAC?
In ΔABD and ΔBAC,
AD = BC (Given)
∠BAD = ∠CBA (Given)
AB = BA (Side common to both triangles)
Hence ΔABD∼ΔBAC
(by SAS similarity condition)
Thus, ∠ABD = ∠BAC
(Corresponding parts of similar triangles)