In the below-shown figure if AP=BP, AQ=BQ, then can we say that APBQ forms a kite. State true/False.
True
In the given figure,
PA=PB (Given)
AQ=BQ (Given)
AB is perpendicular to PQ.
Since all the sides are not equal and the diagonals are perpendicular. The given figure is not a rhombus but it is a kite.