In the below shown reaction sequence, the compound B formed is :
$C H_{3} C H_{2} C H_{2} O H P C l_{3} - -- \to A a l c . K O H - ----- \to B$

propane

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propanol

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propene

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propyne

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Solution

The correct option is B propene
Alcohols react with $P C l_{3}$ to give alkyl halides, which react with alcoholic KOH to undergo $E_{2}$ elimination to give alkenes.

Reaction:

$C H_{3} C H_{2} C H_{2} - O H P C l_{3} - -- \to C H_{3} C H_{2} C H_{2} - C l a l c . K O H - ---- \to C H_{3} - C H = C H_{2}$

So, A is 1-Chloropropane and B is propene.

Option C is correct.

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Similar questions

C H_{3} C H_{2} C H_{2} O H P C l_{5} - -- \to A a l c o h o l i c - ---- \to K O H

C H_{3} C H_{2} C H_{2} O H P C l_{5} ⟶ A a l c o h o l i c - ---- \to K O H B

C H_{3} - C H_{2} - C H_{2} - C l (a) p r o p y l c h l o r i d e) A l c . K O H - ----- \to C H_{3} - C H = C H_{2} (P r o p e n e b)

B

C H_{3} C H_{2} C H_{2} O H P C l_{3} \to A A l c . K O H \to B

The compound (B) formed in the following sequence of reactions

$C H_{3} C H_{2} C H_{2} O H P C l_{5} - -- \to (A) a l c . K O H - ---- \to (B)$

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