Question

In the Bohr model of the hydrogen atom, the ratio of the kinetic energy to the total energy of the electron in a quantum state $n$ is k. Then |k| (magnitude of k) is

Answer 1

$\begin{array}{c}n=\text{no. of energy level}\\ z=\text{Atomic no.}\end{array}$

$\begin{array}{c}\text{Total energy}=-13.6\times \frac{n^2}{z^2}\\ \text{Kinetic Energy}=13.6\times \frac{n^2}{z^2}\end{array}$

$\begin{array}{c}\text{Ratio of}K\cdot E\text{to Total energy}=|k|=1\\ \text{Answer}=1.\end{array}$