Question

In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportional to (n = principle quantum number)

• A. $n$
• B. $n^{-1}$
• C. $n^2$
• D. $n^{-2}$

Answer 1

The correct option is C $n^2$

Bohr radius $r=\frac{{\in }_0{n}^2{h}^2}{\pi Zm{e}^2}$