Question

In the Bohr's model of $H$-atom, the ratio of kinetic energy to the total energy of the electron in the quantum state $n$ is :

Answer 1

In the nth quantum state, the relationship between total energy (T.E), kinetic energy (K.E) and potential energy (P.E) is
$T.E=K.E+P.E$
But $P.E=-2K.E$
Hence, the expression for total energy becomes
$T.E=K.E+(-2K.E)=-K.E$
.Hence, the ratio of kinetic energy to the total energy of the electron in the quantum state n is 1.