Question

In the Bohr's model of the hydrogen atom, the ratio of the kinetic energy to the total energy of the electron in a quantum state $n$ is:

• A. $1$
• B. $2$
• C. $-1$
• D. $-2$

Answer 1

Answer: (C)

$-1$

As we know, in Bohr model $KE$ of an electron in an orbit $=+\frac{1}{2}\frac{e^2}{r_n}$
Total energy of electron in an orbit $=\frac{-e^2}{2r_n}$
$\therefore \frac{KE}{TE}=-1$