Question

In the Bohr’s model of hydrogen atom, the electrons moves around the nucleus in a circular orbit of a radius $5\times {10}^{-11}$ metre. It’s time period is $1.5\times {10}^{-16}$ sec. The current associated is

• A. Zero
• B. $1.6\times {10}^{-19}A$
• C. $0.17A$
• D. $1.07\times {10}^{-3}A$

Answer 1

The correct option is D $1.07\times {10}^{-3}A$

$i=\frac{q}{T}=\frac{1.6\times {10}^{-19}}{1.5\times {10}^{-16}}=1.07\times {10}^{-3}A$