In the Cannizzaro reaction given below- 2Ph - CHO PH - CH2OH - PhCO2- the slowest step is-

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The Cannizaro Reaction

In the Canniz...

Question

In the Cannizzaro reaction given below:
$2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}$ the slowest step is:

The attack of

⊖ O H

at the carbonyl group

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The transfer of hydride to the carbonyl group.

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The abstraction of proton from the carboxylic acid.

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The deprotonation of

P h - C H_{2} O H .

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Solution

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2 P h - C H O {O H}^{-} - ---------- \to P h - C H_{2} - O H + P h C O_{2}^{-}

2 P h - C H O - O H ⟶ P h - C H_{2} O H + P H C O_{2}^{\oplus}

2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}

P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}

2 P h C H O O H^{-} - -- \to p h C H_{2} + p h C O_{2}^{-} .

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