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Question

# In the Carius method for the estimation of halogen, 0.15 g of an monobromo organic compound gave 0.12 g of AgBr. The percentage of bromine in the compound is: (Atomic mass of Br = 80 u, Ag = 108 u)

A
34.04%
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B
66.04%
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C
44.04%
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D
54.04%
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Solution

## The correct option is A 34.04%(Given: Atomic mass of Br = 80 u, Ag = 108 u) Molar mass of bromine = 80 g/mol Molar mass of AgBr = 188 g/mol Mass of AgBr = 0.12 g Mass of organic compound = 0.15 g mass of the organic compoundmass of AgBr=molar mass of the organic compound molar mass of AgBr 0.150.12=molar mass of the organic compound188 0.15×1880.12=molar mass of the organic compound the % of bromine in the organic compound,= molar mass of Brmolar mass of the organic compound×100 =80×0.120.15×188×100=34.04%

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