In the case of alkali metals, the covalent character decreases in the order:

M F > M C l > M B r > M I

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M F > M C l > M I > M B r

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M I > M B r > M C l > M F

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M C l > M I > M B r > M F

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Solution

The correct option is C $M I > M B r > M C l > M F$
The covalent character of any compound in general depends upon size of the anion. The larger the anion, greater is its polarizability. Therefore, $M I > M B r > M C l > M F$ .

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