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In the cell P...

Question

In the cell Pt(s)\vert H_2(g, 1bar)\vert HCl(aq)\vert AgCl(s)\vert Ag(s)\vert Pt(s) the cell potential is 0.92 when a 10^{-6}molal HCl solution is used. The s†an dard electrode potential of (AgCl/Ag,Cl –) electrode is : (1) 0.20 V (2) 0.76 V (3) 0.40 V (4) 0.94 V ?

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P t (s), H_{2} (g) | 1 b a r H C l (a q) | A g (s) | P t (s)

0.92

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E_{A g^{+} / A g}^{0} = 0.77 V a n d E_{C d^{2 +} / C d}^{0} = - 0.40

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0.7991 V

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K_{s p} = 1.56 \times 10^{- 10}

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