Question

In the characteristic X-ray spectra, the frequency of $K_{\alpha }$ line is:

• A. greater than that of $K_{\beta }$ line
• B. less than that of $K_{\beta }$ line
• C. equal to that of $K_{\beta }$ line
• D. equal to that of $L_{\alpha }$ line

Answer 1

The correct option is B less than that of $K_{\beta }$ line

${\lambda }_{\alpha }=\frac{hc}{E_K-E_L}$

${\nu }_{\alpha }=\frac{E_K-E_L}{h}$

${\nu }_{\beta }=\frac{E_K-E_M}{h}$

$\because E_K-E_M>E_K-E_L$

$\therefore {\nu }_{\beta }>{\nu }_{\alpha }$