Question

In the chemical reaction $C{l}_2+H_{2}S⟶2HCl+S$, the oxidation number of sulphur changes from

• A. 0 to 2
• B. 2 to 0
• C. 2 to 0
• D. -2 to -1

Answer 1

The correct option is C 2 to 0

The oxidation state of sulphur in $H_{2}Sis-2$, while it is zero in 'S' i.e. in this reaction oxidation of sulphur and reduction of chlorine takes place. The oxidation number of chlorine changes from 0 to -1.