Question

In the chemical reaction, $K_{2}C{r}_2{O}_7+x{H}_{2}S{O}_4+yS{O}_2\to K_{2}S{O}_4+C{r}_2(S{O}_4{)}_3+z{H}_{2}O$. the values of x, y and z respectively are.

• A. $x=1,y=3,z=1$
• B. $x=4,y=1,z=4$
• C. $x=3,y=2,z=1$
• D. $x=2,y=2,z=2$

Answer 1

Answer: (A)

$x=1,y=3,z=1$

Total number of sulphur atoms on reactant side $=$ Total number of sulphur atoms on product side

$x+y=4$ --- equation (1)

Total number of hydrogen atoms on reactant side $=$ Total number of hydrogen atoms on product side

$2\left(x\right)=2\left(z\right)$ means $x=z$ --- equation (2)

Total number of oxygen atoms on reactant side $=$ Total number of oxygen atoms on product side

$4\left(x\right)+7+2\left(y\right)=4+12+z$ ---equation (3)

On solving above three equations, we get

$x=1,y=3,z=1$.