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Capacitance of a Random Conductor

In the circui...

Question

In the circuit as shown in figure if all the symbols have their usual meanings, then identify the correct statement :

q_{2} = q_{2}; V_{2} = V_{3}

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q_{1} = q_{2} + q_{3}; V_{2} = V_{3}

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q_{1} = q_{2} + q_{3}; V_{1} + V_{2} + V_{3}

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q_{1} + q_{2} + q_{3} = 0; V_{2} = V_{3} = V - V_{1}

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Solution

The correct option is B $q_{1} = q_{2} + q_{3}; V_{2} = V_{3}$
As $C_{1}$ and combine $(C_{2}, C_{3})$ are in series so charge on $C_{1} =$ charge on $(C_{2}, C_{3})$
i.e, $q_{1} = q_{2} + q_{3}$
As $C_{2}$ and $C_{3}$ are in parallel so potential across each is same. i,e $V_{2} = V_{3}$
Here, $V = V_{1} + V_{2} o r V = V_{1} + V_{3}$

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Similar questions

C_{1}, C_{2}

C_{3}

In an adjoining figure are shown three capacitors C₁,C₂ and C₃ joined to a

battery. The correct condition will be (Symbols have their usual meanings)

Q_{1}, Q_{2}

Q_{3}

v_{1}, v_{2}, v_{3}

v_{1} > v_{2} > v_{3}

v_{1} = v_{2} > v_{3}

v_{2} > v_{3} > v_{1}

v_{1} > v_{3} > v_{2}

- q_{1}, + q_{2}

- q_{3}

- q_{1}

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