In the circuit, as shown in the figure, if the value of R.M.S current is 2.2 A, the power factor of the box is
1√2
1
√32
12
Z=Vi⇒R2+(XL+XC)2=(2202.2)2⇒XL=XC=100Ω; Z of the box =√R2+X2C ⇒Z=100√2. Power factor of the box =RZ.