In the circuit diagram, all the bulbs are identical. Bulb will be the brightest.
A
A
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B
B
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C
C
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D
D
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Solution
The correct option is C C Always the brightest bulb will be the one with the highest power dissipation. P=i2R.
So since R is the same for all bulbs, we just have to find which bulb has highest current.
If current through D is i, Then through A and B is i2 (Since that branch has double the resistance, and hence half the current), and through C is 3 i2.
Therefore Obviously C will glow the brighest.