In the circuit diagram, Find:

(i) total resistance

(ii) current shown by the ammeter A

Open in App

Solution

(i) For total resistance

$R_{1}$ = $R_{2}$ = 5 $Ω$ are in parallel

$R_{p}$ = $\frac{5 \times 5}{5 + 5}$ = $\frac{25}{10}$ = 2.5 $Ω$

(ii) For circuit current

Potential difference, V = 4 V

Circuit resistance $R_{p}$ = 2.5 $Ω$

Circuit current, I = ?(To be calculated)

From Ohm's law,

R = $\frac{V}{I}$

Then, I = $\frac{V}{R}$

I = $\frac{4}{2.5}$ = 1.6 A

So, Ammeter reads 1.6 A current

Suggest Corrections

Similar questions

(a) With the help of a circuit diagram, obtain the relation for the equivalent resistance of two resistances connected in parallel.
(b) IN the circuit diagram shown below, find:
(i) Total resistance.
(ii) Current shown by the ammeter A

Q. (a) With the help of a circuit diagram, obtain the relation for the equivalent resistance of two resistances connected in parallel.
(b) In the circuit diagram shown below, find:

(i) Total resistance.
(ii) Current shown by the ammeter A

Q. As shown in following circuit

A, B

and

C

are three ammeter.

0.5 A

current is shown by ammeter

B

.
(a) Find the current passing through Ammeter

A

and

C

.
(b) Find total resistance of circuit.
(c) Find emf of the battery (Take resistance of each ammeter as zero.)

Q. (a) With the help of a diagram, derive the formula for the resultant resistance of three resistors connected in series.
(b) For the circuit shown in the diagram given below:

Calculate:
(i) the value of current through each resistor.
(ii) the total current in the circuit.
(iii) the total effective resistance of the circuit.

Q. A cell, a resistor, a key and ammeter are arranged as shown in the circuit diagrams of Figure (i), (ii) and (iii). The current recorded in the ammeter will be

Join BYJU'S Learning Program

In the circuit diagram, Find: (i) total resistance (ii) current shown by the ammeter A

(i) For total resistance R1 = R2 = 5 Ω are in parallel Rp = 5×55+5 = 2510 = 2.5 Ω (ii) For circuit current Potential difference, V = 4 V Circuit resistance Rp = 2.5 Ω Circuit current, I = ?(To be calculated) From Ohm's law, R = VI Then, I = VR I = 42.5 = 1.6 A So, Ammeter reads 1.6 A current

In the circuit diagram, Find:

(i) total resistance

(ii) current shown by the ammeter A