In the circuit diagram given below five resistances of 10 - 40 - 30 - 20 - and 60 - are connected as shown to a 12 V battery- Calculate - a total resistance in the circuit- b total current flowing in the circuit-

In case of series connection, the total resistance = R1 + R2 + R3 + R4 + R5 = 10 + 40 + 30 + 20 + 60 = 160 ohm the total current flowing through the circuit ...

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Byju's Answer

Standard X

Physics

Equivalent Resistance of a System of Resistor

In the circui...

Question

In the circuit diagram given below five resistances of $10 Ω, 40 Ω, 30 Ω, 20 Ω, a n d 60 Ω$
are connected in series to a 12 V battery.

Calculate :
(a) the total resistance in the circuit.
(b) the total current flowing in the circuit.

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Solution

In case of series connection,

a) The total resistance = $R = R_{1} + R_{2} + R_{3} + R_{4} + R_{5}$

= 10 + 40 + 30 + 20 + 60

= 160 ohm

b) The total current flowing through the circuit = I =V/R

= 12/160

=0.075A

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In the circuit diagram given below five resistances of 10Ω,40Ω,30Ω,20Ω,and60Ω are connected in series to a 12 V battery. Calculate : (a) the total resistance in the circuit. (b) the total current flowing in the circuit.

In case of series connection, a) The total resistance = R=R1+R2+R3+R4+R5 = 10 + 40 + 30 + 20 + 60 = 160 ohm b) The total current flowing through the circuit = I =V/R = 12/160 =0.075A

In the circuit diagram given below five resistances of $10 Ω, 40 Ω, 30 Ω, 20 Ω, a n d 60 Ω$
are connected in series to a 12 V battery.

Calculate :
(a) the total resistance in the circuit.
(b) the total current flowing in the circuit.

In case of series connection,

a) The total resistance = $R = R_{1} + R_{2} + R_{3} + R_{4} + R_{5}$

= 10 + 40 + 30 + 20 + 60

= 160 ohm

b) The total current flowing through the circuit = I =V/R

= 12/160

=0.075A