In the circuit diagram given below, the value of the potential difference across the plates of the capacitors are:
A
17.5kV,7.5kV
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B
10kV,15kV
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C
5kV,20kV
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D
16.5kV,8.5kV
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Solution
The correct option is A17.5kV,7.5kV Charge on both capacitors must be same as they are in series. applying KVL ⇒−13×103+Q7×10−6=0 ⇒Q10−6(1021)=25×103 ⇒Q=21×25×102×10−610 V accrors 3μF=21×25×10−43×10−6=17.5×103V V accross 7μF=21×25×10−47×10−6=7.5×103V