Question

In the circuit diagram shown below :

• A. The effective capacitance between A and C is $\frac{3}{2}\mu F$
• B. The effective capacitance between A and C is $\frac{5}{2}\mu F$
• C. The potential difference between A and B in steady state is $\frac{75}{2}$ volt
• D. The potential difference between B and C in steady state is $\frac{75}{2}$ volt

Answer 1

Answer: (B), (D)

The correct options are
B

The effective capacitance between A and C is $\frac{5}{2}\mu F$

D

The potential difference between B and C in steady state is $\frac{75}{2}$ volt

Given circuit reduces to

$C_{eq}=2.5\mu FQ=CV=1.5\times {10}^{-6}\times 50=75\times {10}^{-6}C{V}_B-V_A=\frac{75\times {10}^{-6}}{6\times {10}^{-6}}=12.5volt{V}_C-V_B=50-12.5=37.5V=\frac{75}{2}volt{V}_C-V_B=\frac{75}{2}volt$