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Question

In the circuit diagram shown, XC=100 Ω,XL=200 Ω and R=100 Ω. The effective current through the source is:


A
20.4 A
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B
2 A
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C
22 A
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D
0.5 A
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Solution

The correct option is C 22 A

Given:
XC=100 Ω
XL=200 Ω
R=100 Ω

Current through the resistor branch
IR=VR=200100=2 A

& current through the LC branch

I=VXLXC=200100=2 A

Therefore, effective current drawn from the source

I=I2R+(I)2=22 A


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