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Question

In the circuit diagram shown, XC=100Ω,XL=200ω and R=100ω. Find the effective current through the source.
793683_fb270a16a466485fadf7cc4d5c60eb4c.png

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Solution

Admittance =Y
Given, XC=100Ω,XL=200Ω and R=XLXC=100Ω
Y=1R+j1(XLXC)
|Y|=(1R)2+(1100)2=(1100)2+(1100)2=2100
Current through source, I=VY=200×2100=22A

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