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Resistors in Series and Parallel

In the circui...

Question

In the circuit element given here, if the potential at point B is zero, i.e., $V_{B} = 0$ , then the potential difference (in volts) between points A and D, i.e., $V_{A} - V_{D}$ is

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Solution

$V_{A} - V_{B} = i \times 1.5 Ω$

Here $i = 1 A$

then $V_{A} - V_{B} = 1 \times 1.5 = 1.5 V$

But $V_{B} = 0$ [given]

$∴ V_{A} = 1.5 + V_{B} = 1.5 V . . . (1)$

$V_{B} - V_{C} = 1 \times 2.5$

$V_{B} - V_{C} = 2.5 V$

or $V_{C} = V_{B} - 2.5 = - 2.5 V$

$V_{C} - V_{D} = - 2 V$

$∴ V_{D} = V_{C} + 2 = - 2.5 + 2$

or $V_{D} = - 0.5 V . . . . (2)$

$V_{A} - V_{D} = 1.5 - (- 0.5)$ ( from (1) and (2) )

$V_{A D} = 2 V$

Hence, potential difference between A and D is 2 V.

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Resistors in Series and Parallel

Standard XII Physics

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