In the circuit given, power developed across 1Ω,2Ω and 3Ω resistances are in the ratio of
1 : 2 : 3
4 : 2 : 27
6 : 4 : 9
2 : 1 : 27
P=i2RCurrent through1Ω is 2i/3Current through1Ω is i/3P1:P2:P3=(4/9):(2/9):3=4:2:27