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In the circui...

Question

In the circuit given, power developed across 1Ω,2Ω and 3Ω resistances are in the ratio of

A

1 : 2 : 3

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B

4 : 2 : 27

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C

6 : 4 : 9

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D

2 : 1 : 27

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Solution

The correct option is B
4 : 2 : 27

$P = i^{2} R Current through 1 Ω i s 2 i / 3 Current through 1 Ω i s i / 3 P_{1} : P_{2} : P_{3} = (4 / 9) : (2 / 9) : 3 = 4 : 2 : 27$

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