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Byju's Answer
Standard XII
Physics
Alternating Current Applied to an Inductor
In the circui...
Question
In the circuit, given power factor of box is 0.5 and power factor of circuit is
√
3
2
. Current is leading the voltage. Resistance used in box is.
Open in App
Solution
Power factor is
cos
ϕ
⇒
for box
cos
ϕ
=
0.5
i
.
e
ϕ
=
60
∘
⇒
t
a
n
60
∘
=
X
C
R
.....(1)
For full circuit:
⇒
c
o
s
ϕ
=
√
3
2
⇒
ϕ
=
30
∘
t
a
n
30
∘
=
X
C
R
+
10
.....(2)
By (1) & (2)
3
=
R
+
10
R
R
=
5
Ω
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