In the circuit of above questions the current in the arm BC will be

\frac{2 i}{5}

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\frac{3 i}{5}

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\frac{4 i}{5}

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\frac{i}{5}

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Solution

The correct option is D $\frac{i}{5}$
In above fig: $i_{1} = \frac{3}{5} i & i_{2} = \frac{2}{5} i$

Therefore current in BC is $i_{3} = 2 i_{2} - i_{1} = \frac{4}{5} i - \frac{3}{5} i = \frac{1}{5} i$

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Express the following complex numbers in the standard form a + i b :

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