2362
You visited us
2362
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Physics
Alternating Current Applied to an Inductor
In the circui...
Question
In the circuit shown above, switch
S
is closed at time
t
=
0
. Find the current through the inductor as a function of time
t
.
Open in App
Solution
At
t
=
0
, Current through inductor will be zero.
At
t
=
∞
, Net emf
=
2
/
2
+
4
/
1
1
/
2
+
1
/
1
=
10
3
V
Net resistance
=
2
×
1
2
+
1
=
2
3
Ω
∴
i
=
10
/
3
2
/
3
=
5
A
To find equivalent time constant short circuit both the batteries and find net resistance across inductor:
R
n
e
t
=
2
×
1
2
+
1
=
2
3
Ω
∴
τ
L
=
L
R
n
e
t
=
1
×
10
−
3
2
/
3
=
3
2000
s
Current through inductor will increase exponentially from
0
to
5
A
,
i
=
5
⎛
⎜
⎝
1
−
e
−
2000
t
3
⎞
⎟
⎠
Suggest Corrections
0
Similar questions
Q.
Switch S is closed in the circuit at time t=0. Find the current through the capacitor and the inductor at any time t.
Q.
Consider the circuit shown in figure. (a) Find the current through the battery a long time after the switch S is closed. (b) Suppose the switch is again opened at t = 0. What is the time constant of the discharging circuit? (c) Find the current through the inductor after one time constant.