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Kirchoff's Voltage Law

In the circui...

Question

In the circuit shown below $E_{1} = 4.0 V, R_{1} = 2 Ω, E_{2} = 6.0 V, R_{2} = 4 Ω$ and $R_{3} = 2 Ω$ . The current $I_{1}$ is

A

1.6 A

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B

1.8 A

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C

1.25 A

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D

1.0 A

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Solution

The correct option is B 1.8 A
Applying Kirchhoff's law for the loops (1) and (2) as shown in figure For loop(1)

$- 2 i_{1} - 2 (i_{1} - i_{2}) + 4 = 0 \Rightarrow 2 i_{1} - i_{2} = 2 . . . . (i)$
For loop (2)
$- 2 (i_{1} - i_{2}) + 4 i_{2} - 6 = 0 \Rightarrow - i_{1} + 3 i_{2} = 3 . . . (i i)$
On solving equation (i) and (ii) $i_{1} = 1.8 A .$

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Kirchoff's Voltage Law

Standard XI Physics

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