In the circuit shown below emf of each batter y is 5V; and has an internal resistance of 1.0Ω.The current in the circuit (I0) and the reading in an ideal voltmeter (V) are
A
I0=1A,V=0
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B
I0=5A,V=0
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C
I0=1A,V=1
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D
I0=5A,V=1
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Solution
The correct option is BI0=5A,V=0 Equivalent emf of the circuit Eeq=E+E+E+E+E+E+E+E=8E ∴Eeq=8×5=40V Equivalent resistance of circuit req=8r=8×1=8Ω Current through the circuit Io=Eeqreq=408=5V Voltmeter reading V=E−Ir=5−5×1=0