Question

In the circuit shown below, the circuit turn off time of thyristor is

Answer 1

Circuit turn off time of thyristor $=\frac{\pi +2{\theta }_1}{\omega }$

For value of ${\theta }_1$
$V_m\sin {\theta }_1=E$

or $230\sqrt{2}\sin {\theta }_1=100$

or ${\theta }_1={\sin }^{-1}\left(\frac{100}{230\sqrt{2}}\right)={17.90}^0$

$t_c=\frac{\pi +\left(\frac{2\times {17.90}^0\times \pi }{{180}^0}\right)}{2\pi \times 50}$

= 11.99 ms