Question

In the circuit shown below, the magnitude of current (in ampere) that flows from a to b when switch S is closed, is

Answer 1

When S is closed, no current through $5\Omega$ resistor because it is short - circuited So, current will pass from b to a and then $10\Omega$



the $10\Omega$ resistor is directly connected across the cell
From V= IR (ohm's law), the current through $10\Omega$ resistor

$I=\frac{10V}{10\Omega }=1A\to$ this is from b to a.

So current from a to b = -I = - 1 A
Hence magnitude of current from a to b = 1 A.