wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the circuit shown below, the magnitude of current (in ampere) that flows from a to b when switch S is closed, is


Open in App
Solution

When S is closed, no current through 5Ω resistor because it is short - circuited So, current will pass from b to a and then 10 Ω



the 10 Ω resistor is directly connected across the cell
From V= IR (ohm's law), the current through 10 Ω resistor

I=10V10Ω=1A this is from b to a.

So current from a to b = -I = - 1 A
Hence magnitude of current from a to b = 1 A.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon