In the circuit shown below,

The magnitude of maximum value of current through capacitor is

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Solution

When thyristor $T_{1}$ is on, the capacitor current is,

$i_{c} (t) = \frac{2 V_{s}}{R_{2}} e^{- t / R_{2} C}$

${| I_{C} |}_{p e a k} = \frac{2 V_{s}}{R_{2}} = 2 A$

and when thyristor $T_{2}$ is on, the capacitor current is,

$i_{c} (t) = \frac{2 V_{s}}{R_{1}} e^{- t / R_{1} C}$

${| I_{C} |}_{p e a k} = \frac{2 V_{s}}{R_{1}} = \frac{2 \times 100}{10} = 20 A$

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