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Question

In the circuit shown below, the norton equivalent current in amperes with respect to the terminals P and Q is

A
6.4 - j4.8
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B
6.56 - j7.87
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C
10 + j0
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D
16 + j0
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Solution

The correct option is A 6.4 - j4.8
For norton equivalent current short circuiting the terminal PQ.

Short circuit current,

Isc=2515+j30+25×1600

=2540+j30×1600=(25×16)005036.86

=836.860

Hence Norton current is

IN=ISC=836.860

IN=(6.4j4.8)A

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