Question

In the circuit shown below, the voltmeter reads 10 V.



(a) What is the combined resistance?
(b) What current flows?
(c) What is the p.d. across 2 Ω resistor?
(d) What is the p.d. across 3 Ω resistor?

Answer 1

(a) The resistors of 2 Ω and 3 Ω are connected in series.
Therefore their combined resistance, R = R₁ + R₂
Here, R₁=2 Ω
R₂=3 Ω
So, the combined resistance, R = 2 Ω + 3 Ω
R = 5 Ω

(b) The current, I in the circuit can be calculated as:
V = IR
or I = 10 / 5 = 2 At)=R2R1+R2v(t)
(c) The p.d. across the 2 Ω resistor is:
V = IR
or V = 2$\times$2= 4 V

(d) The p.d. across the 3 Ω resistor:
V = IR
or V = 2 x 3
or V = 6 V