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Standard XII

Physics

Phasor

In the circui...

Question

In the circuit shown below , transistor M1 is in saturation and has transconductance $g_{m} = 0.01 S$ . Ignoring internal parasitic capacitances and assuming the channel length modulation $λ$ to be zero, then the small signal input pole frequency (in kHz) is

None

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87.57 kHz

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57.87 kHz

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75.78 kHz

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Solution

The correct option is C 57.87 kHz
With respect to AC

Taking Miller's equivalent and assume $r_{0} = \infty$

$A_{V} = - g_{m} R_{D} = - 0.01 \times 10^{3}$

Small signal input pole frequency,

$f = \frac{1}{2 π R C}$

where C is the input capacitance after taking miller circuit

$C = C_{i n} (1 - A_{v})$

$= \frac{1}{2 π \times 5 \times 10^{3} \times 50 \times 10^{- 12} (1 + 10)}$

= 57.87 kHz

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In the circuit shown below , transistor M1 is in saturation and has transconductance gm=0.01S . Ignoring internal parasitic capacitances and assuming the channel length modulation λ to be zero, then the small signal input pole frequency (in kHz) is

The correct option is C 57.87 kHzWith respect to AC Taking Miller's equivalent and assume r0=∞ AV=−gmRD=−0.01×103 Small signal input pole frequency, f=12πRC where C is the input capacitance after taking miller circuit C=Cin(1−Av) =12π×5×103×50×10−12(1+10) = 57.87 kHz

In the circuit shown below , transistor M1 is in saturation and has transconductance $g_{m} = 0.01 S$ . Ignoring internal parasitic capacitances and assuming the channel length modulation $λ$ to be zero, then the small signal input pole frequency (in kHz) is