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Question

In the circuit shown below , transistor M1 is in saturation and has transconductance gm=0.01S . Ignoring internal parasitic capacitances and assuming the channel length modulation λ to be zero, then the small signal input pole frequency (in kHz) is

A
None
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B
87.57 kHz
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C
57.87 kHz
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D
75.78 kHz
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Solution

The correct option is C 57.87 kHz
With respect to AC

Taking Miller's equivalent and assume r0=

AV=gmRD=0.01×103

Small signal input pole frequency,

f=12πRC

where C is the input capacitance after taking miller circuit

C=Cin(1Av)

=12π×5×103×50×1012(1+10)

= 57.87 kHz

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