In the circuit shown, cells are of equal emf E but of different internal resistances r1=6Ω and r2=4Ω . Reading of the ideal voltmeter connected across cell 1 is zero. Value of the external resistance R in ohm is equal to
A
2
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B
2.4
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C
10
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D
24
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E
Zero
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Solution
The correct option is A 2 Let, current i flows through the circuit. For current through cell 1, we can write, E−ir1=0 ∴i=Er1 and for current through R we can write, (E+E)−i(r1+r2+R)=0 ∴i=2Er1+r2+R
Using value of i, Er1=2Er1+r2+R ∴R=r1−r2 ∴R=6−4=2Ω