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Question

In the circuit shown, charge on the 5μF capacitor is


A
18.00 μC
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B
10.90 μC
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C
16.36 μC
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D
5.45 μC
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Solution

The correct option is C 16.36 μC

Let q1 and q2 be the charge on the capacitors of 2μF and 4μF. Then charge on capacitor of 5μF

Q=q1+q2

5V0=2(6V0)+4(6V0)
5V0=122V0+244V0
11V0=36V0=3611V
Q=5V0=18011=16.36 μC

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