In the circuit shown, current through 25 V cell is

7.2 A

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10 A

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12 A

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14.2 A

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Solution

The correct option is C $12 A$
Applying $K V L$ in loops $C D B A C, E F B A E, G H B A G, a n d I J B A I$ .
We get:
$30 - i_{1} \times 11 = - 25$ or $i_{1} = 5 A$
$20 + i_{2} \times 5 = 25$ or $i_{2} = 1 A$
$5 - i_{3} \times 10 = - 25$ or $i_{3} = 3 A$
$10 + i_{4} \times 5 = 25$ or $i_{4} = 3 A$
Current through $25 V$ cell is $i_{1} + i_{2} + i_{3} + i_{4} = 12 A$

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