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Question

In the circuit shown, current through 25 V cell is

157312_ba54e94aa0994022b7f7485176a808e5.png


A
7.2A
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B
10A
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C
12A
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D
14.2A
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Solution

The correct option is C $$12 A$$
Applying $$KVL$$ in loops $$CDBAC, EFBAE, GHBAG, \: and \: IJBAI$$. 
We get:
$$30 - i_1 \times 11 =-25$$ or $$i_1=5\, A$$
$$20 + i_2 \times 5 =25$$ or $$i_2=1\, A$$
$$5 - i_3 \times 10 =-25$$ or $$i_3=3\, A$$
$$10 + i_4 \times 5 =25$$ or $$i_4=3\, A$$
Current through $$25 V$$ cell is $$i_1 + i_2 + i_3 + i_4 = 12 \, A$$

327725_157312_ans_ef98d96783114acab12800266a8b7ac4.png

Physics

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