In the circuit shown, current through 25 v cell is

7.2 A

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10 A

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11A

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None of these

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Solution

The correct option is C 11A
$I = I_{1} + I_{2} + I_{3} + I_{4} = \frac{30}{11} + 4 + 2 + 2 = \frac{30 + 44 + 44}{11} = \frac{30 + 88}{11} = \frac{11.8}{11} = 10.7 = 11 A$

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25

25 V

2 Ω

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