In the circuit shown emf E=10V, Resistance R=1Ω and coil inductances L1=1HandL2=2H are known. The internal resistance of the source and the coil are negligible. The steady state currents in the coils L1andL2 after switch S was closed:
A
i1=103A,i2=203A
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B
i1=i2=103A
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C
i1=203A,i2=103A
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D
i1=i2203A
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Solution
The correct option is Di1=203A,i2=103A i1×1=i2×2 and i1+i2=101=10 3(i2)=10 i2=103 i1=203