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Byju's Answer

Standard XII

Physics

Parallel Combination of Cells

In the circui...

Question

In the circuit shown here $E_{1} = E_{2} = E_{3} = 2 V$ and $R_{1} = R_{2} = 4 Ω$ . The current flowing between point A and B through battery $E_{2}$ is

Zero

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2 A from A to B

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2 A from B to A

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None of these

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Solution

The correct option is B 2 A from A to B
The equivalent circuit can be drawn as since $E_{1}$ and $E_{3}$ are parallely connected

So current $i = \frac{2 + 2}{2} = 2 A m p$ from A to B

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Similar questions

Q. In the circuit shown here

E_{1} = E_{2} = E_{3} = 2 V

and

R_{1} = R_{2} = 4 Ω

. The current flowing between point A and B through battery

E_{2}

Q. In the circuit shown in Figure,

E_{1} = E_{2} = E_{3} = 2 V

and

R_{1} = R_{2} = 4 Ω

. The current flowing between points

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E_{1} = E_{2} = E_{3} = 2 V

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Q. In the circuit shown in figure,

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and

r_{1} = r_{2} = r_{3} = 1 o h m

(a) Find the potential difference between the points

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and the currents through each branch.
(b) If

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Two resistances R₁ and R₂ are joined with two batteries of emf E₁and E₂. If E₂ is short circuited, the current through R₁is

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In the circuit shown here E1=E2=E3=2V and R1=R2=4Ω. The current flowing between point A and B through battery E2 is

The correct option is B 2 A from A to B The equivalent circuit can be drawn as since E1 and E3 are parallely connected So current i=2+22=2 Amp from A to B

In the circuit shown here $E_{1} = E_{2} = E_{3} = 2 V$ and $R_{1} = R_{2} = 4 Ω$ . The current flowing between point A and B through battery $E_{2}$ is

The correct option is B 2 A from A to B
The equivalent circuit can be drawn as since $E_{1}$ and $E_{3}$ are parallely connected

So current $i = \frac{2 + 2}{2} = 2 A m p$ from A to B