Question

In the circuit shown, if a conducting wire is connected between points A and B, the current in this wire will

• A. Flow from A to B
• B. Flow in the direction which will be decided by the value of V
• C. Be zero
• D. Flow form B to A

Answer 1

The correct option is D Flow form B to A

This is not a Wheatstone circuit since

$\frac{4}{1}\ne \frac{4}{3}$.


current in upper wire,
$I_1=\frac{4}{4+8}I=\frac{4I}{12}=\frac{I}{3}$
current in lower wire,
$I_2=I-\frac{I}{3}=\frac{2I}{3}$
Let $c$ is the leftmost junction,
For wire $CA$,
$V_c-\frac{4I}{3}=V_A$
For wire $CB$,
$V_c-\frac{2I}{3}=V_B$
From above two equations we can clearly say,
$V_B>V_A$
Current flows from higher potential to lower potential, so it flows from B to A.