In the circuit shown in fig., all wires have equal resistance R (=5Ω). The equivalent resistance between A and B:
A
10/7 Ω
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B
15/4 Ω
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C
7 Ω
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D
3 Ω
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Solution
The correct option is C 3 Ω Simplified circuit is shown as below.. By wheatstone condition, the circuit is reduced to as shown [ED and FC can be removed] 1Req=115+115+15 or, 1Req=215+15=515=13 or, Req=3Ω