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Question

In the circuit shown in Fig. the sources have emf's ε1=1.5 V,ε2=2.0 V,ε3=2.5 V, and the resistances are equal to R1=10Ω,R2=20Ω,R3=30Ω. The internal resistances of the sources are negligible. Find:
(a) the current flowing through the resistance R1;
(b) a potential difference φAφB between the points A and B.
1194073_1796f90f76b247a1959c0ecdf779a51c.jpg

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Solution

At first indicate the currents in the branches using charge conservation (which also includes the point rule).
In the loops 1 BA 61 and B34AB from the loop rule, φ=0, we get, respectively
ξ2+(ii1)R2+ξ1i1R1=0(1)
iR2+ξ3(ii1)R2+ξ2=0(2)
On solving Eqs (1) and (2), we obtain
i1=(ξ1ξ2)R3+R2(ξ1+ξ3)R1R2+R2R3+R3R10.06 A
Thus φAφB=ξ2i2R20.9V.

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